2020 WAEC GCE/WASSCE PRIVATE SECOND SERIES PHYSICS PRACTICAL QUESTIONS/ANSWERS VERIFIED EXPO

(3)
Tabulate
Mc= 0.0725kg , θr= 29°c

S/n; 12345

Vi(cm); |50|70|90|110|130

θI(°c); |38|36|35|34|33

Mw=d*v(kg); 0.05|0.07|0.09|0.11|0.13

T=(θ-θr)°c; 9|7|6|5|4

T¹(/°c); 0.11|0.14|0.17|0.20|0.25

(3)
Graph

(3vi)
Slope S= Dm/DT^-¹ = 0.11-0.05/0.20-011=0.06/0.09=0.67kgk

(3vii)
Interprets C = – 0.022kg

(3viii)
C=McK/4200
K=4200c/mc= 4200*0.022/0.0725
= -1,274.5

(3ix)
(i)it was ensure that the mixture is heated and allowed to boil for 3 minutes
(ii)error due to parallax when reading the thermometer was avoided

(3bi)
The specific heat of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. The units for specific heat can either be joules per gram per degree (J/g°C) or calories per gram per degree (cal/g°C). This text will use J/g°C for specific heat.

(3bii)
Power =Hot=6300*(50-30)*12*60
=9,072,000J=9.072MJ
=====================================

(1)
Tabulate
S/n ; 1|2|3|4|5
Xi/Cm; |6.50|6 00|5.50|5.00|4.50

Xi/cm; |32.50|30 00|27.50|25.00|22.50

Mg/I; |100.00|120.00|150.00|170.00|22000|

Xi^-¹/cm^-¹; |0.031|0.033|0.036|0.04|0.044|

Graph.

(1ix)
Slope S = DXi^-¹/cm^-¹/Δm/g = 0.044-0.031/220-100 =1.083*10^-⁴

(1x)
S=1.083*10^-⁴ =1/45(50+Mr)
50 + Mr = 1/45*1.083*10^-⁴
=205.13
Mr=205.13-50=155.13gcm

(1xi)
(i)I close the window to avoid air resistance during balancing of the meter rule
(ii)I took my reading at eye level to avoid error due to parallax

(1bi)
(i)wide base
(ii)low center of gravity

(1bii)
(i)the applied force about O point
(ii)the radius of rotation at a point

Posted by admin on 21st November 2020.

Tags: 2021 waec gce, 2021 waec gce answers, 2021 waec gce physics, 2021 wassce private, 2021 wassce private second series, 2021 wassce second series

Categories: Waec Gce