logo



student ONLINE CANDIDATES : 48




PAYMENT FOR WAEC AND JAMB EXPO HAS STARTED, PAY NOW!!!



neco runs

WAEC / NECO / NABTEB /GCE SUBSCRIPTION PAYMENT EXPO


HOW TO PAY FOR WAEC/ NECO/ NABTEB /GCE ANSWER:

ALL SCIENCE ANSWERS + PRACTICAL COST: N5,500

ALL ART OR COMMERICAIL ANSWERS COST #4,500

 

WHATSAPP US AND SEND:- EXAM TYPE + MTN-CARD + PHONE NUMBER + SUBJECT TO 09055986588 (ONLY ON WHATSAPP)

UPDATE: Our Waec, Neco and Nabteb Exam Runs Payment is on, Earlyanswer is 100% Legit (Invite Your Classmates,Friends Here)

Answer Page

Answer Page

Confirmation page

Verify NECO / WAEC Payment

EARLYANSWER OFFICIAL WHATSAPP GROUP

JOIN OUR GENERAL WHATSAPP GROUP




« PREVIOUS POST:

| NEXT POST:

»

2020 WAEC GCE/WASSCE PRIVATE SECOND SERIES PHYSICS OBJ ESSAY QUESTIONS AND ANSWERS

 

Physic-Ob!

Pls Trace It From Your Objective.

[If you see any options here pick it from your objective thank You.]

1. Gravitational force

2. Kinetic or potential

3. Violet

4. Tesla

5. Electric motor

6. Loudness

7. Electric field

8. Constriction

9. Lead

10. Good absorbers of radiant heat are good emitters

11. Decrease

12. Sound wave
13. 

14 I and IV only

15. Diaphragm

16. Multiplier is high resistance change it to voltmeter

17. P is at the level with Q

18. 34.0⁰C

19. 0.02secs

20. 2.7*10kg/m³

21. Centripetal force applied in the wheel rotates it

22. Mg(sθ-μcosθ)

23.0.60Ω^-¹m^-¹

24. 800N

25. Both earth and Moon travel around the sun

26. 0.04secs

27. 0.25*10³Ω

28. 2uf

29. Radiate specific values of energy of electromagnetic waves

30. 6m/s²

31. 0.67

32. Axe

33. Mass of the conductor

34. 20ms^-¹

35. Charge ionises the sorrounding air

36. East west

37. 33.3A

38. 27.8m

39. 17N

40. 40g

41. Critical angle

42. Momentum

43. Mixture of gases

44. J

45. Jumps to a higher permissible energy level

46. Mass of the liquid

47. Spring balance

48. Argon

49. Images are formed behind the mirror always

50. Charles coloumb

===========================

PART I
ANSWER FIVE (5) ONLY.

=====================================

(6)
Me = 9.1*10-³¹kg
V = 1.0*10⁶m/s
h = 6.6*10-³⁴Js
λ = h/MeV
λ = 6.6*10-³⁴/9.1*10-³¹*1.0*10⁶
= 0.7252*10-⁹
λ = 7.25*10-¹⁰m

=================================

(5a)
Forbidden gap is the group of energy levels that cannot be occupied by the electrons, these energies lies in between conduction band and valence band.
(5b)
(i) free electrons which have negative charges
(ii) holes, which have positive charges

================================

(1)
(i)They are use to find the unit of a given physical quantity in a given system of units.
(ii)They are use to find dimensions of physical constants or coefficients.
(iii)They are use to convert a physical quantity from one system of units to another.

====================================

(2a)
Time of flight: Time of flight (T) is the time required for a projectile to return to the Same level from which it was projected
T= 2usin θ / g
(2b)
Maximum height: Maximum height(H) is the highest vertical distance attained as measured from the horizontal projectile plane.
H = U²sin²θ / 2g
(2c)
Range : Range(R) is defined as the horizontal distance from the point of projection to the point where the projectile hits the projection plane again
R= U²sin2θ / g
=======================================
(7a)
Magnetic materials are materials studied and used mainly for their magnetic properties. The magnetic response of a materials is largely determined by the magnetic dipole moment associated with the intrinsic angular momentum, or spin, of its electrons.
(7b)
(i)by heating past the Curie point
(ii)by applying a strong magnetic field
====================================
PART II
ANSWER 3 ONLY.
======================================
(8ai)
Work is said to be done whenever a force moves a body through a certain distance in the direction of force and is equal to the product of the force and the distance moved.
(8aii)
Workdone = Force * distance
= F*S
F = m(v/t)
Workdone = m(v/t) * 1/2vt
= 1/2mv²
Ek = 1/2mv²
ie workdone = change in kinetic energy of the body
(8bi)
Kinetic friction is the force that must be overcome so that a body can move with uniform speed over another body
(8bii)
(i)Nature of surfaces in contact
(ii)Depends on the normal force pressing the surfaces together
(8ci)
Tc – umg = ma
Tc – (0.3 * 3* 10)= 3*2
Tc – 9 = 6
Tc = 9+6 = 15N
(8cii)
TB – 2umg = ma
TB – 2(9)= 3*2
TB = 6+18
TB = 24N
(8ciii)
TA – 3umg = ma
TA – 3(9) = 3*2
TA – 27 = 6
TA = 6+27
TA = 33N

======================================

(11ai)

Reactance is the opposition of a circuit element to the flow of current due to that element’s inductance or capacitance.

(11aii)

Impedance is measure of the opposition to the flow of alternating current through a circuit

(11aiii)

(11bi)

Half-life, in radioactivity; is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive.

(11bii)

(11c)

Donor Impurity; is a dopant having 5 electrons in its valence shell when doped with a semiconductor to increase its conductivity is known as a donor impurity. In other words It holds the ability to donate an extra electron present in its valence shell to the neighbouring atom.

=================================
(9ai)
Heat describes the transfer of thermal energy between molecules within a system and is measured in Joules. Heat measures how energy moves or flows. … Temperature describes the average kinetic energy of molecules within a material or system and is measured in Celsius (°C), Kelvin(K), Fahrenheit (°F), or Rankine (R).
(9aii)
The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. While The upper fixed point, is the temperature of pure boiling water at normal atmospheric pressure.
(9bi)
Kink or construction
(9bii)
Fine narrowbore
(9biii)
Thing glass tube or bulb
(9ci)
Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature. If a specimen increases in length from l1 to l2 when its temperature is raised θ°, then the expansivity (α) is given by: l2 = l1(1 + αθ).
(9cii)
Let initial length of brass rod be Lbo
Let initial length of iron rod be Lio
At 20⁰C , Lbo – Lio = 28cm
At 90⁰C, Lb = Lbo( 1*∝b∆∅)= Lbo( 1+0.00133)
Li = Lio( 1+∝i∆∅) = Lio(1+0.00084)
Lb – Li = 28cm
1.00133Lbo – 1.00084Lio = 28
ie 1.00133Lbo – 1.00084Lio = Lbo – Lio
Lio – 1.00084 = 1.00133 – Lbo
1.00084Lio = 1.00133Lbo
Lio = (1.00133/1.00084)Lbo
Lio = (133/84)Lbo
Initial length of iron rod = 133/84 of initial length of brass rod

Posted by on 21st November 2020.

Tags: , , , , ,

Categories: Waec Gce

HOW TO WIN MTN CARD FROM EARLYANSWER
 
CLICK HERE TO SHARE THIS WEBSITE TO YOUR WHATSAPP FRIENDS / GROUPS AND WIN MTN CARD NOW

Chat Admin After You Share To 20 People On Whatsapp to Redeem The Price

Click here to submit your phone number for free updates about WAEC, NECO, NABTEB, GCE.

2023/2024 EXAM RUNS UPDATES👇

CLICK HERE TO GET WAEC 2023 EXAM RUNS


CLICK HERE TO GET NECO 2023 EXAM RUNS


CLICK HERE TO GET NABTEB 2023 EXAM RUNS


Our Answer Page for All Examination

One Response

  1. Iderawumi

    by I want to get answer to gce questions on Oct 8, 2022

Leave a Reply

« PREVIOUS POST:

| NEXT POST:

»