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# 2020 WAEC GCE/WASSCE PRIVATE SECOND SERIES PHYSICS PRACTICAL QUESTIONS/ANSWERS VERIFIED EXPO

##### (3) Tabulate Mc= 0.0725kg , θr= 29°c S/n; 12345 Vi(cm); |50|70|90|110|130 θI(°c); |38|36|35|34|33 Mw=d*v(kg); 0.05|0.07|0.09|0.11|0.13 T=(θ-θr)°c; 9|7|6|5|4 T¹(/°c); 0.11|0.14|0.17|0.20|0.25 (3) Graph (3vi) Slope S= Dm/DT^-¹ = 0.11-0.05/0.20-011=0.06/0.09=0.67kgk (3vii) Interprets C = – 0.022kg (3viii) C=McK/4200 K=4200c/mc= 4200*0.022/0.0725 = -1,274.5 (3ix) (i)it was ensure that the mixture is heated and allowed to boil for 3 minutes (ii)error due to parallax when reading the thermometer was avoided (3bi) The specific heat of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. The units for specific heat can either be joules per gram per degree (J/g°C) or calories per gram per degree (cal/g°C). This text will use J/g°C for specific heat. (3bii) Power =Hot=6300*(50-30)*12*60 =9,072,000J=9.072MJ ===================================== (1) Tabulate S/n ; 1|2|3|4|5 Xi/Cm; |6.50|6 00|5.50|5.00|4.50 Xi/cm; |32.50|30 00|27.50|25.00|22.50 Mg/I; |100.00|120.00|150.00|170.00|22000| Xi^-¹/cm^-¹; |0.031|0.033|0.036|0.04|0.044| Graph. (1ix) Slope S = DXi^-¹/cm^-¹/Δm/g = 0.044-0.031/220-100 =1.083*10^-⁴ (1x) S=1.083*10^-⁴ =1/45(50+Mr) 50 + Mr = 1/45*1.083*10^-⁴ =205.13 Mr=205.13-50=155.13gcm (1xi) (i)I close the window to avoid air resistance during balancing of the meter rule (ii)I took my reading at eye level to avoid error due to parallax (1bi) (i)wide base (ii)low center of gravity (1bii) (i)the applied force about O point (ii)the radius of rotation at a point

Posted by on 21st November 2020.

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