logo



student ONLINE CANDIDATES : 151




PAYMENT FOR WAEC AND JAMB EXPO HAS STARTED, PAY NOW!!!



neco runs

WAEC / NECO / NABTEB /GCE SUBSCRIPTION PAYMENT EXPO


HOW TO PAY FOR WAEC/ NECO/ NABTEB /GCE ANSWER:

ALL SCIENCE ANSWERS + PRACTICAL COST: N5,500

ALL ART OR COMMERICAIL ANSWERS COST #4,500

 

WHATSAPP US AND SEND:- EXAM TYPE + MTN-CARD + PHONE NUMBER + SUBJECT TO 09055986588 (ONLY ON WHATSAPP)

UPDATE: Our Waec, Neco and Nabteb Exam Runs Payment is on, Earlyanswer is 100% Legit (Invite Your Classmates,Friends Here)

Answer Page

Answer Page

Confirmation page

Verify NECO / WAEC Payment

EARLYANSWER OFFICIAL WHATSAPP GROUP

JOIN OUR GENERAL WHATSAPP GROUP




« PREVIOUS POST:

| NEXT POST:

»

2024 NECO GCE PHYSICS OBJ AND ESSAY ANSWER

Physics OBJ
1-10: CACABDBECA
11-20: CCDBBDEECA
21-30: ECACEDACDB
31-40: CADBBDCBBC
41-50: EBCADACDAE
51-60: CDCBCEDCCB
=====================================

(15a)
The charge on a body can be identified using a gold leaf electroscope as follows:
By touching the body to the brass disc: Let the electroscope be charged with positive charge. The leaves will be in diverged position. The body to be tested is touched with the brass disc of the electroscope and the divergence of leaves is observed.

Case (i): If the leaves diverge more, the body is positively uncharged. When the body touches the electroscope, its charges are transferred to the leaves. There is an increase in repulsion which happens due to increase in the same kind of charge, and hence, this indicates that the body is positively charged.

Case (ii): If the divergence of the leaves decreases, the body is negatively charged. When the body touches the electroscope, its charges are transferred to the leaves. There is a decrease in repulsion which happens due to decrease in the same kind of charge or increase in opposite kind of charge, and hence, this indicates that the body is negatively charged.

(15b)
F = Gm₁m₂/r²
F = mg

If m₁ = m₂
Gm₁m₂/r² = mg
.:. g = Gm/r

(15c)
R1 = 2ohms
R2 = 3ohms
First connected in parallel
1/RT = 1/2 + 1/3
1/RT = 3+2/6
1/RT = 5/6
5RT = 6
RT = 6/5
RT = 6/5ohms

To a 120v
V = IR
I = 120/6/5
I = 120÷6/5
I = 120 × 5/6
I = 100A

But when connected in series
RT = R1 + R2
RT = 2 + 3
RT = 5ohms

To a 120v
V = IR
I = V/R
I = 120/5
I = 24A
So the difference between the two arrangement in current
[100 – 24]A
= 76A

(12ai)
The volume of a stone is measured using a measuring cylinder by firstly measuring the volume of water in cylinder (v2) , then the stone is dropped into the cylinder (v2)
Let v1 = volume of water without stone
V2 = volume of water and stone.
Therefore the volume of stone = v2 – v1

(12aii)
(i) Nature of the liquid.
(ii) Volume of the liquid.
(iii) Shape of the container of the liquid.

(12bi)
A body is said to be on dynamic equilibrium if the body is moving continually with a constant acceleration.

(12bii)
Draw the diagram

Fy = 0(at equilibrium)
Fa + Fb – W1 – W2 = 0
Fb = W1+W2-Fa ….(1)
Taking moment about point A
W1 × 0.02 + W2×0.05 – Fb×0.07 = 0
0.07Fb = 0.02W1 + 0.05W2
Fb = 2W1+5W2/7 …(2)

(12ci)
Draw the diagram
u = 7m/s
Time of flight = 10s

Time of flight (T) = 2usinΦ/g
10 = 2×70sinΦ/10
140sinΦ = 100
sinΦ = 100/140 = 0.7143
Φ = sin-¹(0.7143)
Φ = 45.58°
Φ = 46°

(12cii)
Maximum height = u²sin²Φ/g
H = 70²sin²45.58/2×10
H = 4900×0.7143²/20
H = 125m
Maximum height = 125m

(2a)
(i) Acceleration
(ii) Velocity

(2b) MSR = 8.5mm
VSR = 15mm
TSR = MSR + VSR
= 8.5 + 15
= 23.5mm

(3i)
draw the velocity diagram

(3ii)
Total distance coverd = 75m
Total distance = Area of shape water graph

75m = 1/2(45) * U
75 = 22.5U
U = 75/22.5
U = 3.33m/s

(4a)
(i) Nuclear fission
(ii) Discharge of fossil fuels such as oil, gas and coal to the atmosphere

(4b)
h = 1.6m
V = ?
g = 10m/s²
V² = u²+2gh
V² = 2×10×1.8
V² = 36m/s
V = √36
= 6m/s

(5)
U1 = 4m/s
U2 = 0m/s
M2 = 60g = 0.6kg
M1 = ?
V = 2.5m/s

Using :
M1U1 + M2U2 = ( M1 + M2)V

( M1*4) + ( 0.6*0) = ( M1 + 0.6) * 2.5
4M1 = 2.5M1 + 1.5
4M1 – 2.5M1 = 1.5
1.5M1 = 1.5
M1 = 1.5/1.5
M1 = 1kg

 

(11a)
(i) Negligible mass = Gamma radiation
(ii) Large Ionization Power = Alpha Particle

(11b)
λ=0.693/T½
λ=0.693/18000
λ=0.0000385 s-¹

 

(10a)
Surface tension is the attractive force exerted upon the surface molecules of a liquid by the molecules beneath that tends to draw the surface molecules into the bulk of the liquid and makes the liquid assume the shape having the least surface area.

(10b)
(i) It is in violation of the Heisenberg Uncertainty Principle. The Bohr Model considers electrons to have both a known radius and orbit, which is impossible according to Heisenberg.
(ii) The Bohr Model is very limited in terms of size. Poor spectral predictions are obtained when larger atoms are in question

Posted by on 29th November 2019.

Tags:

Categories: Neco Gce

HOW TO WIN MTN CARD FROM EARLYANSWER
 
CLICK HERE TO SHARE THIS WEBSITE TO YOUR WHATSAPP FRIENDS / GROUPS AND WIN MTN CARD NOW

Chat Admin After You Share To 20 People On Whatsapp to Redeem The Price

Click here to submit your phone number for free updates about WAEC, NECO, NABTEB, GCE.

2023/2024 EXAM RUNS UPDATES👇

CLICK HERE TO GET WAEC 2023 EXAM RUNS


CLICK HERE TO GET NECO 2023 EXAM RUNS


CLICK HERE TO GET NABTEB 2023 EXAM RUNS


Our Answer Page for All Examination

0 Responses

Leave a Reply

« PREVIOUS POST:

| NEXT POST:

»