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2019 NECO GCE PHYSICS PRACTICAL ANSWER

PHYSIC-PRACTICALS-ANSWERS

(1ai -1aiv)
S/N|M(g)|Real values of b(cm)|Converted values of b(cm)| Real Value of d(cm)| Converted values of d(cm)| N = b/d
1 |20 |5.30|26.50|12.9|64.5|0.41|
2 |40 |8.0 |40.0 |10 |50.0|0.80|
3 |60 |9.9 |49.5 |8.3|41.5|1.20|
4 |80 |11.0|55.0 |7.0|35.0|1.50|
5 |100|12.1|60.5 |6.0|30.0|2.0|

(1bi)
(i)the total upward force must balance the downword
(ii) the algebraic sum of all forces act on the body must be equal to zero

(1bii)
CLICK HERE FOR THE IMAGE

 

(1vi)
slope = Y2-Y1/x2-x1
=70-20/1.4-0.4
= 50/1
=50g

(1vi)
(i) I avoid error due to parallel when taking all my reading
(ii)I made sure that the meter rule beconect horizontally before taking my reading

(1a)
CLICK HERE FOR THE IMAGE

(1)
Graph
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(3ai -3aiv)
S/N|R(ohms)|V(v)|I(A)|1/v(A/v)|R-¹(ohm-¹)|
1 | 1.0|1.21|1.80|1.49|1.00
2 | 2.0|1.50|1.50|1.00|0.50
3 | 3.0|1.64|1.36|0.83|0.33
4 | 4.0|1.72|1.29|0.75|0.25
5 | 5.0|1.76|1.23|0.70|0.20

(3av)
PLOT THE GRAPH

(3avi)
Slope = ΔA/V / ΔR-¹
= 1.28 – 0.80/ 0.80 – 0.30
= 0.48/0.50
= 0.96

Intercept (c) = 0.50

(3avii)
(i) I would ensure I made tight connection before taking my reading.
(ii) I would ensure I noted zero error on the voltmeter and Ammeter

(3bi)
Potential difference is the work done in moving a unit charge from a point in electric field to another. It has the unit of Volt.
V = work done/charge

(3bii)
r = 0.5ohms
I = 1.2A
R = ?
E = 3v
E = I(R+r)
E = IR + Ir
E – Ir = IR
R = E – Ir/I
= 3 – 1.2 × 0.5/1 .2
= 3 – 0.6/1.2
R = 2.4/1.2
R = 2 ohms

(3a)
CLICK HERE FOR THE IMAGE

(3b)
CLICK HERE FOR THE IMAGE

(3)
GRAPH
CLICK HERE FOR THE IMAGE

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Posted by on 22nd November 2019.

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