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2019/2020 WAEC GCE PHYSICS PRACTICAL EXPO QUESTIONS AND ANSWERS

 

WAEC GCE PHYSICS PRACTICAL ANSWER

PHYSICS-PRACTICAL
Bonus
(2)
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(2) graph
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======================

 

(1)
TABULATE

i : 1,2,3,4,5,6

Xraw(cm) : 4.9, 6.7, 8.3, 10.0, 11.3, 12.7

Yraw(cm): 5.3, 5.9, 9.7, 11.7, 13.4, 15.0

Xreal(cm): 9.8, 13.4, 16.6, 20.0, 22.6, 25.4

Yreal(cm): 10.6, 11.8, 19.4, 23.4, 26.8, 30.0

 

(1 graph)
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(1v)
Slope (s) = Change in Y/Change in X = Y2 – Y1/X2 – X1

= 26.8-10.6/22.6/9.8 =16.2/12.8
S = 1.266

(1vi)
If S = 1.266
Then K=1/1.266 = 0.790

(1vii)
– I would ensure that the reading was taking from the meniscus level before taking my reading
– I would have ensured that the tubes are vertical upright before carrying out the experiment for accuracy

(1bi)
Pressure : It is the force applied per unit area. It is measured in N/m^2. Pressure = Force/Area

(1bii)
Relative density of E = Y/X = 15/10
= 1.5

 

(1)
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(3)
TABULATE

(i) 1,2,3,4,5,

R(Ohms) : 2.0, 4.0, 6.0, 8.0, 10.0

OP(i)[cm] : 3.70, 4.30, 5.00, 5.40, 5.70

Xi(cm) : 18.50, 21.50, 25.0, 27.0, 28.50

X^-1: 0.054, 0.047, 0.040, 0.037, 0.035

R^-1: 0.500, 0.250, 0.167, 0.125, 0.100

(3iv)
Slope, s= Δx^-1/ΔR^-1 =(50-30)*10^-3/0.29-0.04

= 20*10^-3/0.25 = 0.02/0.25
=0.08

Intercept, c = 26.5*10^-3 = 0.0265

(3vi)
K2 =1/c = 1/0.0265 =37.74
K2 = 5/c = 0.08/0.0265
= 3.02

(3viii)
– I would ensure tight connection
– I would ensure clean terminals

(3bi)
– Hyper accuracy
– No errors in readings associated with the use of a pointer in a voltmeter

(3bii)
E1 = E2
L1 = L2

E2L1=E1L2
When,
E1=IV
E2=?
L1= 50cm
L2= 72cm
50E2 = 72
E2=72/50

E2= 1.444V

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(3b)
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(3c)
Graph
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(3a)
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Posted by on 8th September 2019.

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Categories: Waec Gce

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